5%水泥穩(wěn)定級配碎石配合比中的5%是什么意思？如何計算？

　　What does 5% mean in the mix proportion of 5% cement stabilized graded crushed stone? How to calculate?

　　答：

　　Answer:

　　1、5%是水泥的用量。

　　1. 5% is the amount of cement used.

　　2、是質(zhì)量比或者說是重量比，決不是體積比。

　　2. It's a mass ratio or weight ratio, not a volume ratio.

　　3、采用正推方法，即知道5%的前提下，去計算水泥用量，怎么算？

　　3. Using the forward calculation method, that is, knowing 5% of the premise, how to calculate the cement dosage?

　　水泥：集料=5：100，水泥為集料質(zhì)量的5%，即：5÷100，這就工程上的百分比，而不是數(shù)學(xué)上的。即，以集料為100，另外加入5的水泥。

　　Cement: Aggregate=5:100, cement is 5% of the aggregate mass, which is 5 ÷ 100. This is a percentage in engineering, not in mathematics. That is, with an aggregate of 100, an additional 5% cement is added.

　　例題：某市政道路基層采用18cm+18cm+18cm三層的5%水泥穩(wěn)定級配碎石，擊實試驗取得的最大干密度為2262㎏/m?（2.262g/?），含水量6.4%，則每立方米：

　　Example: A municipal road base uses 5% cement stabilized graded crushed stone with three layers of 18cm+18cm+18cm. The maximum dry density obtained from the compaction test is 2262 kg/m ? (2.262g/?), with a moisture content of 6.4%. Therefore, per cubic meter:

　　水泥用量=2262㎏×5%÷（1+5%）=2262×5÷（100+5）=107.71㎏≈108㎏

　　Cement dosage=2262kg × 5% ÷ (1+5%)=2262kg × 5 ÷ (100+5)=107.71kg ≈ 108kg

　　集料用量=2262-108=2154㎏

　　Aggregate dosage=2262-108=2154kg

　　或2262㎏×1÷（1+5%）=2262×100÷（100+5）=2154.29㎏≈2154㎏

　　Or 2262 kg × 1 ÷ (1+5%)=2262 × 100 ÷ (100+5)=2154.29 kg ≈ 2154 kg

　　用水量=2262㎏×6.4%=144.77㎏≈145㎏

　　Water consumption=2262kg × 6.4%=144.77kg ≈ 145kg

　　所以，5%水泥穩(wěn)定級配碎石配合比=水泥：集料：水

　　So, the mix ratio of 5% cement stabilized graded crushed stone=cement: aggregate: water

　　=108 ：2154 ：145

　　=108 ：2154 ：145

　　≈5 ：100 ：6.72

　　≈5 ：100 ：6.72

　　≈5% ：100% ：6.72%

　　≈5% ：100% ：6.72%

　　4、請計算一下，如果是數(shù)學(xué)意義上的5%水穩(wěn)級配碎石，在工程上是百分之幾？

　　4. Please calculate, what percentage is 5% water stable graded crushed stone in mathematical terms in engineering?

　　水泥：（水泥+集料）=5：（5+95），則

　　Cement: (cement+aggregate)=5: (5+95), then

　　水泥：集料=5：95=5.26%

　　Cement: aggregate=5:95=5.26%

　　答案是：5.26%

　　The answer is: 5.26%

　　所以，工程上的5%若按數(shù)學(xué)上計算則為4.76%。

　　So, if calculated mathematically, the 5% in engineering is 4.76%.

　　以上只是用來計算，實際工程中不采用數(shù)學(xué)意義上的5%～～～

　　The above is only for calculation, and the mathematical 5% is not used in actual engineering

　　5、再請計算一下，某市政道路施工圖紙中對5%水泥穩(wěn)定級配碎石的圖紙說明如下：

　　5. Please calculate again. The drawing description for 5% cement stabilized graded crushed stone in a municipal road construction drawing is as follows:

　　圖片

　　image

　　這樣的水穩(wěn)，水泥用量是百分之幾？

　　What percentage of cement is required for this water stability?

　　答：這個就是設(shè)計單位給的建議，這個就是數(shù)學(xué)意義上的5%了，工程上水泥用量是多少呢？

　　Answer: This is the suggestion given by the design unit, which is 5% in mathematical terms. What is the amount of cement used in engineering?

　　5÷95=5.26%

　　5÷95=5.26%

　　同第4條所述。

　　As stated in Article 4.

　　所以，這個設(shè)計圖紙上設(shè)計單位給的建議，可以不采納，是超標的。對現(xiàn)場施工的工程技術(shù)人員容易引起誤解。

　　So, the suggestions given by the design unit on this design drawing can be ignored, as they exceed the standard. Misunderstandings can easily arise among engineering and technical personnel involved in on-site construction.

　　6、水泥穩(wěn)定級配碎石相關(guān)的規(guī)范、規(guī)程

　　6. Specifications and regulations related to cement stabilized graded crushed stone

　　1）JTG 3432-2024《公路工程集料試驗規(guī)程》，自2024年5月1日開始實施。《公路工程集料試驗規(guī)程》（JTG E42—2005）同時廢止。

　　1) JTG 3432-2024 "Code for Testing of Aggregates in Highway Engineering" will be implemented from May 1, 2024. The "Code for Testing Aggregates in Highway Engineering" (JTG E42-2005) is simultaneously abolished.

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